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Anonymous Posted on Apr 13, 2014

If function with array - Microsoft Excel for PC

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ali_zulfikar

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  • Expert 156 Answers
  • Posted on Sep 16, 2017
ali_zulfikar
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Here is an example:-
We have to calculate result on the basis of marks.
1. Select answer range and click in formula bar
2. Type following formula
=if(d5:D9>=40,"Passed","Failed")
3. Now Press CTRL+SHIFT+Enter key
4. Observe the result in answer range and formula in formula bar, notice { } braces come automatically when we press CTRL+SHIFT+Enter key for an array.
if function with array - excel3-yi4l5i2224qkwob0czw2k0fe-5-0.png For more clarification please mail on ali_zulfikar@yahoo.com with screenshots.

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Can my HP disk array withstand extreme pressure changes?

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My MS Excel vlookup function ASCII type table contains both upper case and lower case letters, characters like ( and % or *, and numbers. It seems to return the numerical equivalent of upper case letters...

Correct a #N/A error blueup_clv.gifShow All bluedrop_clv.gifHide All This error occurs when a value is not available to a function or formula.
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tip

HOW TO COUNT THE OCCURRENCES OF A TEXT STRING

In the cell that you want the result to appear in, enter the appropriate formula from the following examples.
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Use this formula
=SUM(IF(range=number,1,0))
where range is the range that you want to search, and number is the number that you want to count.
NOTE: This formula must be entered as an array formula. To enter an array formula, press CTRL+SHIFT+ENTER.
How to Count the Occurrences of a Text String
Method 1
Use this formula
=SUM(IF(range="text",1,0))
where range is the range that you want to search, and text is the text that you want to find (the text must be enclosed in quotation marks).
NOTE: The above formula must be entered as an array formula. To enter an array formula, press CTRL+SHIFT+ENTER.
Method 2
Use the COUNTIF() function to count the occurrences of a text string. For example, use the formula
=COUNTIF(range,"text")
where range is the range of cells that you are evaluating, and text is the text string that you want to count instances of (note that text must be enclosed in quotation marks).
NOTE: This formula must be entered as an array formula. To enter an array formula, press CTRL+SHIFT+ENTER.
Wildcard characters can be used within the COUNTIF function.
The asterisk character (*) represents more than one character. For example, to count all the cells in the range a1:a10 that contain an "x," you can use the following formula:
=COUNTIF(a1:a10,"*x*")
The question mark character (?) can also be used to represent one wildcard character -- for example, to count all cells in the range whose second character is the letter, such as "ax" or "bx."
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Need an excel formula.

The crude solution is:
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For mor info, see "Lookup and Reference Functions" in the Excel Help.
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Here is an example: Draw Line, Ellipse, Polygon ...

From website above, here is script in JS:

"<script type="text/javascript">
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function myDrawFunction()
{
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jg.paint();

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An array is a series of elements of the same type placed in contiguous memory locations that can be individually referenced by adding an index to a unique identifier
Initializing arrays. When declaring a regular array of local scope (within a function, for example), if we do not specify otherwise, its elements will not be initialized to any value by default, so their content will be undetermined until we store some value in them. The elements of global and static arrays, on the other hand, are automatically initialized with their default values, which for all fundamental types this means they are filled with zeros
include <iostream>
using namespace std;

int billy [] = {16, 2, 77, 40, 12071};
int n, result=0;

int main ()
{
for ( n=0 ; n<5 ; n++ )
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result += billy[n];
}
cout << result;
return 0;
}
multidimensional array pseudo-multidimensional array #define WIDTH 5 #define HEIGHT 3 int jimmy [HEIGHT][WIDTH]; int n,m; int main () { for (n=0;n<HEIGHT;n++) for (m=0;m<WIDTH;m++) { jimmy[n][m]=(n+1)*(m+1); } return 0; } #define WIDTH 5 #define HEIGHT 3 int jimmy [HEIGHT * WIDTH]; int n,m; int main () { for (n=0;n<HEIGHT;n++) for (m=0;m<WIDTH;m++) { jimmy[n*WIDTH+m]=(n+1)*(m+1); } return 0; }
and now for trignometry
#include<iostream>
#include<cmath>
using namespace std;

int main()
{
int factorial(int);
int n = 3, i = 1;
double x, x2, b, PI, r;
char choice;
//r = x * (PI / 180)

cout<<"Please enter an angle value => ";
cin>>x;
cout<<"Is the angle value in Degree or Radian?"<<endl;
cout<<"Type D if its in degree "<<endl;
cout<<"Type R if its in radian "<<endl;
cin>>choice;


if((choice = 'R')||(choice = 'r'))
do{
i++; n = 3; x2 = 0; b = x2;
{
if(i == 1)
x2 = x - (pow(x,n) /factorial(n));
n = n + 2;
};
else
{
x2 = (x2 + ((pow(x,n)) /(factorial(n))) - (pow(x,n+2)) / (factorial(n+2)));
n = n + 4;
}


}while(abs(b - x2) > 0.000001);
else
//convert it to r

r = x * PI /180;

//cout<<"error occured/n";
cout<<"sin(x) = "<<x2<<endl;

return 0;
}
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Excel formula

Yes, there is a function in MS Excel called "sumproduct" which multiplies the componenets in an array or arrays, then totals the result, eg :

=SUMPRODUCT(D4:D20,B4:B20) ...Job done...Enjoy !
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